1/x-5+1/x+5=-3/x^2-25

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Solution for 1/x-5+1/x+5=-3/x^2-25 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x+1/x-5+5 = -3/(x^2)-25 // + -3/(x^2)-25

1/x+1/x-(-3/(x^2))-5+5+25 = 0

1/x+1/x+3*x^-2-5+5+25 = 0

2*x^-1+3*x^-2+25 = 0

t_1 = x^-1

3*t_1^2+2*t_1^1+25 = 0

3*t_1^2+2*t_1+25 = 0

DELTA = 2^2-(3*4*25)

DELTA = -296

DELTA < 0

x belongs to the empty set

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